Rabu, 17 Mei 2017

Using English For Report


Title:Determination of the molar mass based on the freezing point drop
Day/Date:Friday,17th march 2017
Purpose: 1) To be able set the point of freezing pure liquid and freezing point of solution in the solvent
          2) To be able to determine molar mass and unknown compounds based        on the decrease of freezing point
Theoretical basis:
The colligative nature of the solution is the nature of the solution which does not depend on the kind of solute but solely determined by the amount of solute (Syukri,2010:210).
When a solvent is added with a small amount of solute,there will be a solution which decreases the saturated vapor pressure,increase in the the boiling point, decrease the freezing point, osmosis pressure, and others(Elis,2011:201).
The addition of non-volatile solutes into pure liquid causes a drop in the vapor pressure of the liquid. This results in  a decrease in the freezing point of the solution and an increase in the the boiling point of the solution when compared to the pure liquid. How much change occurs depends only on the amount of the dissolved substance and on the dissociation level of the solute. Changes in freezing and boiling points are not related to the chemical identity of the substance in question. Decrease in vapor pressure,boiling point rise, and decrease of freezing point are known as colligative properties(Handayana,2010:298).
There are five koligative properties of the solution:
1. Decrease in saturated vapor pressure,from Roult’s law
The solvent vapor pressure is not zero and changes according to the composition of the solution at a certain temperature. Roult’s law states that the vapor pressure of the solvent above a solution (PA) is equal to the product of vapor pressure because x1 =1-x2. For a solution consisting of two components,Roult’s law is written as:
ΔP1 = P1-P10=x1P01-P10=-x2P¬¬10
So,the change in solvent vapor pressure id directly proportional to the mole fraction of the solute(Oxtoby,2010:309).
2. Osmosis Pressure
The number of particles in the solution is determined by the concentration of the solution and the nature of the solution itself. The number of particles in the non-electrolyte solution is not equal to the number of particles in the electrolyte solution even though the concentrations are the same(Oxtoby,2010:309).
3. Increase of boiling point
The normal boiling point of pure liquid or solution is the temperature at which the vapor pressure reaches 1 atm. Since the solute decreases the vapor pressure, the temperature of the solution should be increased to boil(Oxtoby,2010:310).
4. Decrease of freezing point
If the solvent water and air pressure 1 atm, then the freezing point of the solution is expressed as:
Tf =(0-ΔTf)0C
(Oxtoby,2010:311)
5. Osmotic pressure
This pressure is a pressure applied to a solution which can stop the transfer of solvent molecules into the solution through a semipermeable membrane (osmosis process)(Oxtoby,2010:312).
The concentration of the substance is the number of moles pervolume. Molality is the mass ration and t is independent of temperature. Molality and molarity are almost equal (Bird,2010:257).

Tools and materials:
Tools to be used:
1000 ml beaker
50 ml beaker
Large reaction tube
Thermometer
Spray bottle
Stir bar
Stopwatch
Analytical balance
Materials to be used:
Benzenal (C6H6)
P-xylene
Ice cube
Aquades
Salt

Work steps:























Results:
A. Fozen solvent determination of pure solvent
1. The finally buret reading : -
2. The firstly buret reading : -
3. The volume of p-xylene used : 25 mL











Discussion:
In this experiment,we conducted two types of that,there are:
A.  Frozen solvent determination of pure solvent
In this experiment, we used a p-xylene solvent because this solution was a benzene used as a solvent. The use of salt in this experiment is for as a stabilizer of ice temperature because the salt can inhibit the process of melting ice. Salt used should not be too much because it will affect the process of decrease in freezing and the results will be less accurate. However,if the salt used is too small then the frost drop does not reach an accurte temperature. We use a thermometer to measure the temperature of the solvent when the solvent is frozen but keep the thermometer from touching the bottom of the test tube as it will affect the stability of the freezing point temperature of the tested solution.
From the graph,it can be seen that there is a decrease in temperature every 15 seconds. Although our experiments failed because this solution did not freeze but there was a decrease of temperature from 100 C until -40 C. This indicates that there is an effect if ice used to decrease this freezing point even though it does not freeze. When we see the decrease of temperature in every 15 seconds,it can be seen that the longer time the slower it goes down or change.
B.  Determination of molar masses of unknown compound
For this experiment,we did not do it because this experiment can only be done if the previous experiment successed. But the previous experiment was unsuccessful so we could not determine the molar mass of a compound we didi not know yet. According to the literature,if we have obtained the determination of freezing point of pure solvent,then we can look for the molar mass of unknown compound by the formula:
ΔTf = Tf (pelarut) – Tf (larutan)
Then
ΔTf = Kf . m
This calculation can be done by drawing a line that is at the initial and final temperature when the temperature obtained to the point where the solution or solvent p-xylene freeze.

Conclusion:
For these experiment, we can concluded that:
1.The freezing point of pure liquid and freezing point of solution in the corresponding solvent can be determined by recording the temperature each time continuously, resulting in a constant expressed by:
ΔTf = Kf x m
that : ΔTf = Decrease in freezing point
         Kf = Molar freeze point constant
         M = Molality
2. Determining the molar mass of an unknown compound based on the decrease of freezing point through experiment is by inserting a compound in other compound or other solution. And measured the temperature of any given period of time. These can expressed by:
ΔTf = Kf x m ;n = M x V
Obtained molar: M

Literature:
Syukri,s.2010. Kimia Dasar 2.Bandung:ITB
Handayana,Pudjaamaka.2010.Kimia Fisika Universitas Edisi Ke-6 Jilid 1. Jakarta:Erlangga
Elis.2011.Diktat Kuliah:Kimia Dasar I(Kimia Anorganik).Bandung:ITB
Oxtoby,dkk.2010.Prinsip-prinsip Kimia Modern edisi ke-4 Jilid 1.Jakarta:Erlangga
Bird,Tony.2010.Kimia Fisika Untuk Universitas.Jakarta:PT Gramedia

20 komentar:

  1. Hi Indri, i want to ask. Acetic acid decomposes in water to H+ and C2H3O2. The solution is labeled 0.100 M, acetic acid having freezing point of measurement -0.190 celcius. Calculate the percentage of acetic acid decomposition!

    BalasHapus
    Balasan
    1. ΔTf= 0 – (- 0,19)= 0,19oC
      ΔTf= m Kf i
      0,19= 0,1 x 1,86 (1+α(2-1))
      0,19=0,186 + (1+ α) %=0,02 x 100 %= 2 %.
      (1+ α)=1,02
      α= 1,02-1=0,02.

      Hapus
  2. What effect will there be on calculating the molar mass of each possible error:
    A. A small amount of p-xylene evaporated during the experiment.
    B. The asinmg is present in p-xylene.

    BalasHapus
    Balasan
    1. A. If something like this happens, the volume will decrease so that the molar mass will increase. M = x.
      B. If so, the substance becomes dissolved, thus the molar mass will decrease.

      Hapus
  3. do you think the text report should always have a list of libraries?
    @hudiahudhud

    BalasHapus
    Balasan
    1. Depending on the text we make. If we use the reference book then we must write it in the list of libraries

      Hapus
  4. What affects the decrease of freezing point (Tf) of a solution?

    BalasHapus
  5. What is the relation between molar mass and freezing point?

    BalasHapus
    Balasan
    1. ΔTf = m. Kf
      m=mol.1000/mass of solvent
      Mol=gram/mr(molar mass)

      Hapus
  6. Frozen solvent determination of pure solvent, what does it mean??

    BalasHapus
    Balasan
    1. that's mean that the experiment is to determinated freezing point of pure solvent

      Hapus
  7. Why is the freezing point of a solution down?

    BalasHapus
    Balasan
    1. Because Freezing-point depression is the process in which adding a solute to a solvent decreases the freezing point of the solvent. Examples include salt in water, alcohol in water, or the mixing of two solids such as impurities in a finely powdered drug. In the last case, the added compound is the solute, and the original solid is thought of as the solvent. The resulting solution or solid-solid mixture has a lower freezing point than the pure solvent or solid.

      Hapus
  8. What is the effect on the molar mass if p-xylene evaporates in the experiment?

    BalasHapus
  9. Would you explain to me about the osmotic pressure

    BalasHapus
    Balasan
    1. Osmotic pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of water across a semipermeable membrane.It is also defined as the measure of the tendency of a solution to take in water by osmosis.

      Hapus
  10. why you use Aquades not water in your experiment?

    BalasHapus
    Balasan
    1. This is the different between aquades and just water, Both are just water with ions removed. Distilled water has been deionised by distillation as apposed to another technique such as ion exchange chromotography. The end product is the same and either can be used. Most labs will not have distilled water anyway even if some people still call it distilled rather than deionised.

      Hapus

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